Question

1) write angle of incidence 2) write angle of retraction 3) Use snell's law calculate refractive index
subject physics​

Answer 1

Answer:

Explanation:

In geometric optics, the angle of incidence is the angle between a ray incident on a surface and the line perpendicular to the surface at the point of incidence, called the normal. ... In the figure below, the line representing a ray makes an angle θ with the normal (dotted line).

where i= angle of incidence

and r= angle of refraction

for calculating refractive index, we should know i and r....and...

the values of their respective sines

On putting the values in the formula we can easily find the refractive index

Answer 2

Answer with Explanation:

For part ➀:

• The angle of incidence is the ray of light that passes through the glass.

• Here the arrow pointing downwards indicates that the light is traveling from the above medium to the below medium.

So, Angle of incidence = 30°

For part ➁:

• The angle of refraction is the angle made after passing through a glass object which refracts light.

∴ Angle of refraction = 45°

For part ➂:

Snell's law states that:

$\maltese \: \: \purple{\sf{Refractive \: Index = \dfrac{sin \: \angle i}{sin \: \angle r}}}$

$\implies \sf{Refractive \: Index = \dfrac{sin \: 30^{\circ}}{sin \: 45^{\circ}}}$

$\implies \sf{Refractive \: Index = \dfrac{1}{2} \div \dfrac{1}{\sqrt{2}}}$

$\implies \sf{Refractive \: Index = \dfrac{\sqrt{2}}{2} }$

$\therefore \boxed{\bf{Refractive \: Index = \dfrac{1}{\sqrt{2}} }}$