Question

1. Write detailed answers?

a. Explain the difference between

potential energy and kinetic energy.

b. Derive the formula for the kinetic

energy of an object of mass m,

moving with velocity v.

c. Prove that the kinetic energy of a

freely falling object on reaching

the ground is nothing but the

transformation of its initial potential

energy.

d. Determine the amount of work

done when an object is displaced at

an angle of 300

with respect to the

direction of the applied force.

e. If an object has 0 momentum, does

it have kinetic energy? Explain your

answer.

f. Why is the work done on an object

moving with uniform circular

motion zero?

Answer 1

Here is my solution

Answer 2

Answer:

KE = (1/2)mV²

Explanation:

Potential Energy is the energy of object because of its state of rest or position

PE = mgh

Kinetic Energy is the energy of object because of its state of motion

KE = (1/2)mV²

Let say Object is at height h  & at Rest

so TE = mgh  + (1/2)mv² = mgh = PE

using V² - U² = 2aS

=> V² - 0 = 2gh

so KE at ground = (1/2)m (2gh) = mgh = PE at height h

Hence its transformation of Potential enrgy into kinetic energy

If an object has 0 momentum then it does not have Kinetic enrgy

Momentum = mv

m - mass  v = velocity

if momentum = 0 then

Either m = 0  or v = 0

Kinetic energy = (1/2)mv² = 0  ( of either of m & v is Zero)