(1.) Write the additive inverse of -7/5 .
(2.) Is 7/3 the multiplicative inverse of 2(1/3)? why?
(3.) Multiply 9/14 by the reciprocal of 3(1/3).
(4.) Verify that a+b = b+a, a= -2/3, b= 1/2
(5.) Represent -2/3 on number line.
(6.) Find three rational numbers between 2/3 and 5/8 .
(7.) zero is additive identify. why?
Answers
Answer:
Here's are your answers
Step-by-step explanation:
1. The additive inverse is-7/5 is 7/5.
2. No, it is not the multiplicative inverse of 2(1/3).
3.9/14 ÷10/3
=9/14×3/10
=27/140
4.a÷(b÷c)
=(a÷b)÷(a÷c)
LHS=a÷(b+c)=
b+c
a
RHS=(a÷b)+(a÷c)=
b
a
+
c
a
=
bc
ac+ab
∴LHS
=RHS
a=12,b=1 and c=−2
LHS=a÷(b÷c)=12÷[1÷(−2)]
=12÷
−2
1
=12×1
=12
=−24
RHS=(a÷b)+(a÷c)
=(12÷1)+[12÷(−2))
=12−6
=6
LHS is not equal to RHS (verified)
5. Not done
6.The three rational numbers between 2/3 and 5/8 are 31/48, 63/96, 127/192, 255/384,511/768.
7.Additive identity is a number, which when added to any number, gives the sum as the number itself. ... For any set of numbers, that is, all integers, rational numbers, complex numbers, the additive identity is 0. It is because when you add 0 to any number; it doesn't change the number and keeps its identity.
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