Question

1. Write the chemical formula of following compounds.
a) Ferrous Chloride
b) Aluminum sulphate
c) Calcium phosphate

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2. Calculate the number of mole and molecules in 1.1 g of CO₂ gas.

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Answer 1

Formulas:

a) Ferrous Chloride

=> FeCl3.

b) Aluminum sulphate

=>Al2(SO4)3

c) Calcium phosphate

=>Ca3(PO4)2

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2.Calculate the number of mole and molecules in 1.1 g of CO₂ gas.

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=> No of moles of CO2=actual weight of CO2/Moleculars weight of CO2

Actual weight of CO2=1.1

Melecular weight of CO2=12+32=44 g/mol

n=1.1/44

=11/44x10

=1 g/40 g/mol

G/g will be cut

So,

Mol will went to denominator

1 mol/40=0.025 mol

Now molecules

=>No of Molecules =6.022x10 raise to 23xNo of moles

=>0.1505x10 raise to 23

Explanation:

Hope you find it helpful ✌️

Answer 2

Answer:

Ferrous Chloride

=> FeCl3.

b) Aluminum sulphate

=>Al2(SO4)3

c) Calcium phosphate

=>Ca3(PO4)2

___________________________

2.Calculate the number of mole and molecules in 1.1 g of CO₂ gas.

\Huge{\textbf{\textsf{{\color{navy} {An}} {\purple{SW}} {\pink{ER☆}}{\color{pink} {:}}}}} An SW ER☆ :

=> No of moles of CO2=actual weight of CO2/Moleculars weight of CO2

Actual weight of CO2=1.1

Melecular weight of CO2=12+32=44 g/mol

n=1.1/44

=11/44x10

=1 g/40 g/mol

G/g will be cut

So,

Mol will went to denominator

1 mol/40=0.025 mol

Now molecules

=>No of Molecules =6.022x10 raise to 23xNo of moles

=>0.1505x10 raise to 23

Explanation:

Hope it is helpful to you ♫ ♫ ☆ ☃️ ☆ ♫ ♫