Math, asked by swapnananu75, 4 months ago

1 Write the distance of the point (2, -3) from X axis and Y axis.
2.Write the coefficient of variable 'X' in the linear equation x(x+9) = - x (7-x) + 15​

Answers

Answered by Anonymous
3

\green{\underline{\sf{Question}}:}

1. Write the distance of the point (2, -3) from X axis and Y axis.

2. Write the coefficient of variable 'x' in the linear equation x(x + 9) = -x(7 - x) + 15

\green{\underline{\sf{Solution}}:}

1. Distance from x axis = 3 units towards down

Distance from y axis = 2 units towards right

2. x(x + 9) = -x(7 - x) + 15

→ x² + 9x = -7x + x² + 15

→ 16x = 15

The coefficient of x is 16

Answered by purabihazarikap
3

1. The distance of point P(2,-3) from x-axis and y-axis

is 3 units and 2 units respectively.

2. x(x +9) = -x (7-x) + 15

=> x²+9x = -7x + x² + 15

=> 9x + 7x = 15

=> 16x = 15

Therefore, the coefficient of x in the linear equation

is 16.

Hope it clears all your doubts.

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