Math, asked by Ananthu10, 1 year ago

1) Write the equation :one fifth of m is 5 more than 8
2)An elevator descends into a mine shaft at the rate of 5metre/min.
What will be its position after 30 minutes?

Please answer it's urgent! Fast!

Answers

Answered by shahreyar
1
1) 1/5 of m - 5 =8
2) Distance = Speed * Time
= 5 m/min * 30 min
=150 meter.

Hope u get satisfied with it.
Answered by IPk
0
1.)
 \frac{1}{5}  \times m = 8 + 5
2.)
Descendation rate of the shaft=
5m/min
Therefore, after 30 mins....
 \frac{5m}{1min } \times 30min \\  = 5m \times 30 \\  = 150m
HENCE, After 30 mins the shaft will be -30m.(30m Below the Ground)
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