Question

1) Write the equation :one fifth of m is 5 more than 8
2)An elevator descends into a mine shaft at the rate of 5metre/min.
What will be its position after 30 minutes?

Please answer it's urgent! Fast!

Answer 1

1) 1/5 of m - 5 =8
2) Distance = Speed * Time
= 5 m/min * 30 min
=150 meter.

Hope u get satisfied with it.

Answer 2

1.)
$\frac{1}{5} \times m = 8 + 5$
2.)
Descendation rate of the shaft=
$5m/min$
Therefore, after 30 mins....
$\frac{5m}{1min } \times 30min \\ = 5m \times 30 \\ = 150m$
HENCE, After 30 mins the shaft will be -30m.(30m Below the Ground)