Question

1. Write the first six terms of an AP in which
(d) a = 4, d = 7/3
​

Answer 1

Answer:

4, 19/3 , 26/3 , 33/3 or 11 , 40/3 , 47/3 , 54/3 or 18 , 61/3

Answer 2

AnswEr:-

The First Six terms are:-

• 4
• 19/3
• 26/3
• 11
• 40/3 and
• 47/3.

ExplanaTion:-

Given:-

• First term (a) = 4.

• Common Difference (d) = $\tt\frac{7}{3}$

To Find:-

• The first six terms of that AP.

FormulaUsed:-

$\tt\mapsto a_n = a + (n - 1)d.$

Where,

• $\tt a_n = n^{th}\:\: Term.$

• a = First term.

• n = Number of terms.

• d = Common Difference.

So Here,

• a = 4.

• d = $\tt\dfrac{7}{3}$

And we have to find,

• $\tt a_1 ....... a_6.$

So lets the values in above formula:-

$\tt\mapsto a_n = a + (n - 1)d.$

↦ a2 = a + (2 - 1)d.

↦ a2 = a + d.

↦ a2 = 4 + 7/3.

↦ a2 = 12 + 7/3.

[Taking LCM].

↦ a2 = 19/3.

Similarly,

↦ a3 = a + 2d.

↦ a3 = 4 + 2(7/3).

↦ a3 = 4 + 14/3.

↦ a3 = 12 + 14/3.

↦ a3 = 26/3.

And,

↦ a4 = a + 3d.

↦ a4 = 4 + 3(7/3)

↦ a4 = 12 + 21/3.

↦ a4 = 33/3.

↦ a4 = 11.

Also,

↦ a5 = a + 4d.

↦ a5 = 4 + 4(7/3).

↦ a5 = 12 + 28/3.

↦ a5 = 40/3.

Finally,

↦ a6 = a + 5d.

↦ a6 = 4 + 5(7/3).

↦ a6 = 12 + 35/3.

↦ a6 = 47/3.

So the terms are 4, 19/3, 26/3, 11, 40/3 And 47/3.