Math, asked by mrnakul181, 1 month ago

1. Write the following statements as equations:

(i) Five added to twice a number gives 51.

(ii) One-fifth of 8 taken away from twice a number equals 3.

(iii) The sum of two consecutive even numbers is 102.

(iv) Half of the sum of a number and 5 is 6.​

Answers

Answered by akashray96
1

Answer:

(i)5+2x= 51

Step-by-step explanation:

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Answered by luhagobardhan
0

Answer:

I)let the number be x

and five added to twice means 2x of it

then the result is 51

2x+5=51

ii)let the number be x.

one fifth of 8 means1/5×8is substracted from twice of x

the result is 3

x-(1/5×8)=3

iii)let first even number be x

then the other even consecutive be x+2

their sum is 102

x+ x+2=102

iv)1/2×(x+5)=6

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