Question

1) Write the given quadratic equation in standard form and also write the
values of a, b and c.
4y²-3y=-7​

Answer 1

Step-by-step explanation:

standard form ==> 4y²-3y+7=0

a=4 , b=(-3) , c=7

Answer 2

4y^2 -3y^2 +7 =0

Comparing with

ay^2 + by +c =0

you get

a=+ 4

b= -3

c=+7