1) Write the linear equation such that each point on its graph has an ordinate 3 times its abscissa.
2) If the point (3, 4) lies on the graph of 3y = ax +7, then find the value of a.
3) Draw the graph of the linear equation 3x + 4y = 6.At what points, the graph cuts the x-axis and the y-axis.
Answers
1) Given:
Each point on the graph has an ordinate equal to 3 times its abscissa
To find:
The linear equation satisfying the points
Calculation:
Abscissa generally refers to the horizontal axis (x-axis) and ordinate refers to the vertical axis (y-axis). According to the given data
=> Ordinate = 3(Abscissa)
y = 3(x)
y=3x
Final answer:
The linear equation satisfying the given condition is y=3x
2) if the point (3,4) lies on the given line, x=3 and y=4 will satisfy the given equation.
3y= ax+7
3(4)= a(3)+7
12 = 3a+7
12-7 = 3a
5= 3a
5/3 = a
3) Since we want to draw the graph of linear equation 3x+4y=6 and find at what points , the graph cuts the x – axis and y – axis, I added a picture of the graph bellow.
To compute this analytically you can substitute x by 0 and see what is the value of y, and then do the same for y, substitute it by zero and get the vale of x.
In this case we get (0, 1.5), (1.2, 0)
Refer the attachment friend ↗️↗️
