Question

1. Write the products of each of these reactions.
1. Calcium oxide + water
2. Methane + oxygen
3. Lead + copper chloride →
4. Sodium sulphate + barium chloride →​

Answer 1

1.Calcium hydroxide, also called slaked lime, Ca(OH)2, is obtained by the action of water on calcium oxide. When mixed with water, a small proportion of it dissolves, forming a solution known as limewater, the rest remaining as a suspension called milk of lime.

2One molecule of methane, (the [g] referred to above means it is gaseous form), combined with two oxygen molecules, react to form a carbon dioxide molecule, and two water molecules usually given off as steam or water vapor during the reaction and energy.

3.When lead powder is added to copper chloride solution, a displacement reaction occurs and solid copper is formed.

4.When the solutions of sodium sulphate and barium chloride are mixed a white precipitate is formed which is insoluble in HCl. ... This confirms the presence of sulphate (SO4)2- ions. Reaction: BaCl2(aq) + Na2SO4(s) → BaSO4(s) + NaCl(aq) 1.

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Answer 2

Answer:

1...CaO(s) + H2O (l) → Ca(OH)2(s)

3. Metallic lead Pb(s) displaces copper (II) ions ......Cu2+ from its solution to produce copper metal .....and lead (II) chloride PbCl2 .Jun 18, 2018

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