Question

1) write the sequence of number that leaves a reminder 3 when divided by5?
2) what is the first term and common difference ?
3) Find the algebraic form the sequence?
4) what will be the 40th term of this sequence?
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Answer 1

Answer:

1) Next consider another number which leaves a remainder 3, when divided by 5, say 13. So we can

safely generalize the answer to be 4.

2) An arithmetic sequence is a sequence that has the property that the difference between any two consecutive terms is a constant. This constant is called the common difference. If a1 is the first term of an arithmetic sequence and d is the common difference, the sequence will be: {an}={a1,a1+d,a1+2d,a1+3d,…}

3) 1.step Find the common difference d .

2.step Substitute the common difference and the first term into an=a1+d(n−1) a n = a 1 + d ( n − 1 ) .

3.step Substitute the last term for an and solve for n .

Step-by-step explanation:

hope it helps you