Question

1. Write the standard form of 0.000000159.
2. Write any two perfect square numbers.
3. Find the value of x if 13x + 7 = -9 -3x


7. Find the product of (a+b) and 7a²b
8. Solve : 2x - 3 = x + 2.
​

Answer 1

Step-by-step explanation:

1) 159 × 10^-7 or 1.59 × 10^-9

2) 4, 36

3) 13x + 7 = - 9 - 3x

= 16x = -16

= x = -1

7) (a + b) (7a²b)

= 7a³b + 7a²b²

8) 2x - 3 = x + 2

= x = 5

Answer 2

Answer:

Step-by-step explanation:

1 Standard form = 1.59×10^-7

2 perfect square numbers = 4 and 9

3. 13x+7=-9-3x

13x+3x = -9-7

16x = -16

x = -16/16

x = -1

4. 7a^2b × (a+b)

7a^2b ×a + 7a^2b × b

7a^3b + 7a^2b^2

5. 2x-3 = x+2

2x-x = 2+3

x = 5