Question

1/√x-1 = 1/√x+ 1 ( Find degree and classify as monomial or binomial or trinomial)​​

Answer 1

Solution:

1/√x-1=√x +1

=1/1=√x-1/√x+1 [Alternendo]

=1 =(✓x-1)(√x-1)/(✓x+1)(✓x-1)

=1 =(✓x-1)sq/(✓x)sq - (1)sq

=1 =(✓x)sq-(1)sq +2(✓x)1/x-1

=1 =x-1-2✓x/x-1

=1(x-1)=x-2✓x-1

=x-1+1=x-2✓x

=x =x-2✓x

=x-x+2✓x=0

=2✓x =0

=✓x =0

=x=0sq

x=0

Since,x=O

then,1/✓0-1=1/✓0+1

=1/1=(✓0-1)(✓0-1)/(✓0+1)(✓0-1)

=1/1=((✓0-1)sq/(✓0)sq-(✓1)sq

=1 =(✓-1)sq/-1

=1 =-1/-1

=1 =1/1

=1 =1;a monomial