Question

/1
X
1
-2
= 3, x = 0,2
X​

Answer 1

$\huge\mathbb{↑↑SOLUTION↑↑}$

Answer 2

Simplify:

Step-by-step explanation:

$\ Given \ value:\\\\\frac{1}{x} -\frac{1}{x-2}=3 \\\\\ Solution:\\\\\frac{1}{x} -\frac{1}{x-2}=3 \\\\\rightarrow \frac{x-2-x}{x(x-2)}=3 \\\\\rightarrow -2=3x(x-2) \\\\\rightarrow -2=3x^2-6x \\\\\rightarrow 3x^2-6x +2 =0 \\\\\ apply \ Sridharacharya \ rule: \\\\\ x =\frac{-b\±\sqrt{(b^2 - 4ac)}}{2a}\\\\\rightarrow 3x^2-6x +2 =0 \\\\\rightarrow ax^2+bx +c =0 \\\\a= 3\\b=-6\\c=2 \\\ put \ the \ value \ in \ above \ equation \\\\\ x =\frac{-(-6)\± \sqrt{((-6)^2-4\times 3\times 2)}}{2\times3}$

$\ x =\frac{6\±\sqrt{(36-24)}}{6}\\\\\ x =\frac{6\±\sqrt{(12)}}{6}\\\\\ x =\frac{6\±2\sqrt{3}}{6}\\\\\ x =\frac{2(3\±\sqrt{3})}{6}\\\\\ x =\frac{(3\±\sqrt{3})}{3}$

Learn more:

• Rule: https://brainly.in/question/5396434