1/(x-1) +2/(x-2)=3/(x-3)
Answers
Answered by
0
Answer:
(x−1)(x−2)(x−3)
x−3+x−1
=
3
2
x
3
−6x
2
+11x−6
2x−4
=
3
2
x
3
−6x
2
+11x−6
2(x−2)
=
3
2
x
3
−6x
2
+11x−6
x−2
=
3
1
3x−6=x
3
−6x
2
+11x−6
x
3
−6x
2
+8x=0
x(x
2
−6x+8)=0
x
2
−6x+8=0
Now, solve this equation, to get the value of x ;
\begin{gathered}\mathsf{x {}^{2} - 6x + 8 = 0} \\ \\ \mathsf{x {}^{2} - 4x - 2x + 8 = 0 } \\ \\ \mathsf{x(x - 4) - 2(x - 4) = 0} \\ \\ \mathsf{(x - 2)(x - 4) = 0}\end{gathered}
x
2
−6x+8=0
x
2
−4x−2x+8=0
x(x−4)−2(x−4)=0
(x−2)(x−4)=0
Hence,
\begin{gathered}\mathsf{(x - 2) = 0} \\ \\ \therefore\mathsf{x = 2}\end{gathered}
(x−2)=0
∴x=2
And,
\begin{gathered}\mathsf{(x - 4) = 1} \\ \\ \therefore \mathsf{x = 4}\end{gathered}
(x−4)=1
∴x=4
Step-by-step explanation:
Similar questions
Computer Science,
6 months ago
Physics,
6 months ago
Physics,
10 months ago
Math,
10 months ago
Science,
10 months ago