Math, asked by hatersday769, 8 months ago

1/x+1 + 3/5x+1 =5/x+4

Answers

Answered by Anonymous
0

Answer:

x = 1 or -11/17

Step-by-step explanation:

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Answered by deepak35679
0

Answer:

x = 1 or -9/7

Step-by-step explanation:

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4or, 4(x+2)(x+4) =5(5x2+6x+1)

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4or, 4(x+2)(x+4) =5(5x2+6x+1)or, 4(x2+4x+2x+8) =25x2+30x+5

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4or, 4(x+2)(x+4) =5(5x2+6x+1)or, 4(x2+4x+2x+8) =25x2+30x+5or, 4x2+16x+8x+32 =25x2+30x+5

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4or, 4(x+2)(x+4) =5(5x2+6x+1)or, 4(x2+4x+2x+8) =25x2+30x+5or, 4x2+16x+8x+32 =25x2+30x+5or,25x2-4x2+30x-24x+5-32 = 0

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4or, 4(x+2)(x+4) =5(5x2+6x+1)or, 4(x2+4x+2x+8) =25x2+30x+5or, 4x2+16x+8x+32 =25x2+30x+5or,25x2-4x2+30x-24x+5-32 = 0or, 21x2+6x-27 = 0

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4or, 4(x+2)(x+4) =5(5x2+6x+1)or, 4(x2+4x+2x+8) =25x2+30x+5or, 4x2+16x+8x+32 =25x2+30x+5or,25x2-4x2+30x-24x+5-32 = 0or, 21x2+6x-27 = 0or, 7x2+2x-9 =0

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4or, 4(x+2)(x+4) =5(5x2+6x+1)or, 4(x2+4x+2x+8) =25x2+30x+5or, 4x2+16x+8x+32 =25x2+30x+5or,25x2-4x2+30x-24x+5-32 = 0or, 21x2+6x-27 = 0or, 7x2+2x-9 =0or, 7x2+9x-7x-9 = 0

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4or, 4(x+2)(x+4) =5(5x2+6x+1)or, 4(x2+4x+2x+8) =25x2+30x+5or, 4x2+16x+8x+32 =25x2+30x+5or,25x2-4x2+30x-24x+5-32 = 0or, 21x2+6x-27 = 0or, 7x2+2x-9 =0or, 7x2+9x-7x-9 = 0or, x(7x+9)-1(7x+9) = 0

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4or, 4(x+2)(x+4) =5(5x2+6x+1)or, 4(x2+4x+2x+8) =25x2+30x+5or, 4x2+16x+8x+32 =25x2+30x+5or,25x2-4x2+30x-24x+5-32 = 0or, 21x2+6x-27 = 0or, 7x2+2x-9 =0or, 7x2+9x-7x-9 = 0or, x(7x+9)-1(7x+9) = 0or, (7x+9)(x-1) = 0

1(5x+1)+3(x+1)/(x+1)(5x+1) =5/(x+4)or,5x+1+3x+3/5x2+x+5x+1 =5/x+4or,8x+4/5x2+6x+1 =5/x+4or, 4(x+2)(x+4) =5(5x2+6x+1)or, 4(x2+4x+2x+8) =25x2+30x+5or, 4x2+16x+8x+32 =25x2+30x+5or,25x2-4x2+30x-24x+5-32 = 0or, 21x2+6x-27 = 0or, 7x2+2x-9 =0or, 7x2+9x-7x-9 = 0or, x(7x+9)-1(7x+9) = 0or, (7x+9)(x-1) = 0Therefore, x= 1 or -9/7 Ans

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