1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)=1/6
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Answer:
substitution:
numerator is 1 so that any of the 3,2 values should be 0 (means 1/(x-1)(x-2) or 1/(x-2)(x-3) or 1/(x-3)(x-4) should be zero)
check the values in denominator
check x=1,x=2,x=3,x=4
it is possible for x=4
Step-by-step explanation:
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