Question

1/(x-1) (x-2) +1/(x-2) (x-3) +1/(x-3) (x-4) =1/6
Solve for x

Answer 1

Answer:

1/(x-1)(x-2) + 1/(x-2)(x-3) + 1/(x-3)(x-4) = 1/6

(x-3)(x-4) + (x-1)(x-4) + (x-2)(x-1)/ (x-1)(x-2)(x-3)(x-4) = 1/6

x²-3x-4x+12 + x²-4x-x+4 + x²-x-2x+2/ (x²-2x-x+2)(x²-4x-3x+12) = 1/6

3x²- 15x + 18/ x^4- 10x³+ 35x²-50x +24= 1/6

6[3x²-15x+18] = x^4 - 10x³+35x²-50x+24

18x²-90x +108 = x^4 - 10x³+35x²-50x +24

x^4-10x³+ 35x²-18x² -50x+90x +24 - 108 =0

x^4-10x³+17x²+40x-84=0

and now u can solve the rest!!

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