Question

1/(x-1)(x-2) 1/(x-2)(x-3) = 2/3 solve

Answer 1

Solvina eauatlons
1. Linear or first-degree equations: involving x but not x2 or any
other power of x . Collect x-terms on one side, constant terms on the
other.
ExamDle x+3=7x-4
x + (-7x1 = -4 + (-3)
-6x = -7
x = 7/6
2. Quadratic equations: involving x2 but no higher power of x . These are solved by factoring and/or use of the quadratic formula:
The equation ax2 + bx + c = 0 (a - 0)
has solutions x = 2a
If b2 - 4ac is negative, the equation has no real solutions.
Exam& Solve x2-2x-3=0 for x.
Method: Factoring. x2 - 2x - 3 = (x- 3)(x+1) = 0 . Since a product of two numbers is zero if and only if one of the two
numbers is zero, we must have
x - 3 = 0 or x + I = 0 . So the solutions are x = 3. -1 .
Mefhod: Quadratic formula. a = 1 , b = -2 . c = -3 .
2
X = -(-2) k \/(-2) - 4(1)(-3) . 2 k &i - 2 k 4
2 = 3 or -1
2(1) 2
3. Other types of equations.
14 (a) Solve - - - - I
x+2 x-4
Multiply both sides by common denominator (x+ 2)(x - 4) to get
14(x-4) - 1(x+2) - (x+2)(x-4).