1/(x-1)(x-2) + 1/(x-2)(x-3) = 2/3. where X is not equal to 1, 2, 3. find the value of X
Answers
Answer: 1 + 1 = 2
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(x - 1)(x - 2) (x - 2)(x - 3) 3
1 [ 1 + 1 ] = 2 -------------[Taken 1 / (x - 2) Common ]
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(x - 2) (x - 1) (x - 3) 3
1 [x - 3 + x - 1] = 2
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(x - 2) (x - 1)(x - 3) 3
1 [ 2x - 4 ] = 2
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(x - 2) x² - 4x + 3 3
2x - 4 = 2
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x³ - 4x² - 2x² + 3x - 6 3
2x - 4 = 2
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x³ - 6x² + 3x - 6 3
(2x - 4)3 = 2(x³ - 6x² + 3x - 6)
6x -12 = 2x³ -12x² +6x -12--[6x - 12 gets cancelled on both the sides]
2x³ - 12x² = 0
2x²( x - 6 ) = 0
2x² = 0 OR x - 6 = 0
x = 0 OR x = 6
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