Math, asked by sagarika50, 1 year ago

(1+x)(1+x^2)(1+x^4)(1+x^8)(1-x)​

Answers

Answered by avi851057
4

Answer:

=(1+x)(1-x)(1+x^2)(1+x^4)(1+x^8)

=(1-x^2)(1+x^2)(1+x^4)(1+x^8) :. [(1-x)(1+x)=(1^2-x^2)]

=(1-x^4)(1+x^4)(1+x^8)

=(1-x^8)(1+x^8)

=(1-x^16)

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