Question

1/x-1/x-2=3 find the factor of the equation​

Answer 1

Step-by-step explanation:

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 Roots

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3Solve for x:

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3Solve for x:-(2 x)/(x - 2) = 3

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3Solve for x:-(2 x)/(x - 2) = 3Multiply both sides by x - 2:

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3Solve for x:-(2 x)/(x - 2) = 3Multiply both sides by x - 2:-2 x = 3 (x - 2)

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3Solve for x:-(2 x)/(x - 2) = 3Multiply both sides by x - 2:-2 x = 3 (x - 2)Expand out terms of the right-hand side:

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3Solve for x:-(2 x)/(x - 2) = 3Multiply both sides by x - 2:-2 x = 3 (x - 2)Expand out terms of the right-hand side:-2 x = 3 x - 6

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3Solve for x:-(2 x)/(x - 2) = 3Multiply both sides by x - 2:-2 x = 3 (x - 2)Expand out terms of the right-hand side:-2 x = 3 x - 6Subtract 3 x from both sides:

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3Solve for x:-(2 x)/(x - 2) = 3Multiply both sides by x - 2:-2 x = 3 (x - 2)Expand out terms of the right-hand side:-2 x = 3 x - 6Subtract 3 x from both sides:-5 x = -6

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3Solve for x:-(2 x)/(x - 2) = 3Multiply both sides by x - 2:-2 x = 3 (x - 2)Expand out terms of the right-hand side:-2 x = 3 x - 6Subtract 3 x from both sides:-5 x = -6Divide both sides by -5:

Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 RootsRoots -2/(x-2)x=3Solve for x:-(2 x)/(x - 2) = 3Multiply both sides by x - 2:-2 x = 3 (x - 2)Expand out terms of the right-hand side:-2 x = 3 x - 6Subtract 3 x from both sides:-5 x = -6Divide both sides by -5:Answer: x = 6/5

Answer 2

Answer:

Can we find the roots of 1/x - 1/x-2 = 3 by factorisation method?

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Factor 1/x - 1/(x-2) = 3 = -2/(x-2)x=3 then solve for roots x = 6/5 Roots

Roots -2/(x-2)x=3

Solve for x:

-(2 x)/(x - 2) = 3

Multiply both sides by x - 2:

-2 x = 3 (x - 2)

Expand out terms of the right-hand side:

-2 x = 3 x - 6

Subtract 3 x from both sides:

-5 x = -6

Divide both sides by -5:

Answer: x = 6/5