1-x/1-x² find domain
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Answer:
1-x/1-x2
1-x/(1-x) (1+x)
1/1+x
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Answered by
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Answer:
The domain is x∈R. The range is y∈(0,1]
Step-by-step explanation:
The denominator is = 1+x2
∀x∈R, 1+x2>0
Therefore,
The domain of
f(x) is x∈R
To determine the range, proceed as follows
y= 1
------
1 + 2
y(1+x2)=1
y+yx2=1
yx2=1−yx2=
1 −y
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y
x=√1−y
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y
The range of f[x] is the domain of x
(1−y )>0
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y
y∈R*+
1−y≥0
y≤1
Therefore,
The range is y∈[0,1]
graph{1/(1+x^2) [-11.25, 11.25, -5.625, 5.625]}
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Hope this will help you.
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