Math, asked by choudharyniharika123, 1 year ago

1-x/1-x² find domain​

Answers

Answered by arunkumar5776
0

Answer:

1-x/1-x2

1-x/(1-x) (1+x)

1/1+x

Attachments:
Answered by vedantnaik10
0

Answer:

The domain is  x∈R. The range is  y∈(0,1]

Step-by-step explanation:

The denominator is =  1+x2

∀x∈R,  1+x2>0

Therefore,

The domain of  

f(x) is  x∈R

To determine the range, proceed as follows

y=       1  

      ------

      1 + 2

y(1+x2)=1

y+yx2=1

yx2=1−yx2=

    1  −y

     -----

       y

x=√1−y

    -----

      y

The range of  f[x]  is the domain of  x

(1−y  )>0

-----

 y

y∈R*+

1−y≥0

y≤1

Therefore,

The range is  y∈[0,1]

graph{1/(1+x^2) [-11.25, 11.25, -5.625, 5.625]}

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Hope this will help you.

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