Question

1/x+1/y+1/z=-2 ,1/x-2/y+1/z=3 , 2/x-1/y+3/z=-1​

Answer 1

Answer:

Step-by-step explanation:lets take 1\x as a

                                                            1\y as b

                                                            1\z as c

so a+b+c=-2 ........1    

     a-2b+c=3 ..........2

     2a-b+3c=-1.......3

first solve 1 and 2

a+b+c=-2

a-2b+c=3

3b=-5

b=-5/3

1\y=-5/3

y=-3/5

now solve 1 and 3

a+b+c=-2

2a-b+3c=-1

3a+4c=1......4

solve 2 and 3

a-2b+c=3

2a-b+3c=-1

-a-b-2c=4............5

substitude the value of b in 5

-a-(-5/3)-2c=4

3a+6c=-7.......6

solve 4 and6

3a+4c=1

3a+6c=-7

c=-4

substude cin any 1 eq

3a-16=-7

3a=9

a=3

a=1/x   x=1/3

c=1/z     z=-1/4

hope it helped..................