1/x+1/y=12;3/x-2/y=1
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let us take 1/x as p and 1/y as q
acc /question
p + q =12 and 3p -2q =1
acc to elimination method
(p+q=12)2.
(3p -2q=1)1
2p +2q =24
3p-2q==1
5p =25
p=25/5=5
so we got5=p
then 3p -2q=1 substitute the value of p
15-2q =1
-2q=1-15
-2q=-14
q=-14/-2=7now q we get as 7
therefore 1/x=5=x=1/5
1 /y=7y=1/7
hope it will help you
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