Question

1/x + 1/y = 12 ;3/x-2/y = 1 solve by simultaneous equation

Answer 1

Step-by-step explanation:

Given  

1/x + 1/y = 12 ;3/x-2/y = 1 solve by simultaneous equation

• We need to solve by simultaneous equation.
• So given equations are
• 1/x + 1/y = 12 multiply by 3
• 3/x – 2/y = 1
• So we get
• 3/x + 3/y = 36
• 3/x – 2/y = 1
• Subtracting we get
• 3/y + 2/y = 35
• 5/y = 35
• Or y = 1/7
• Substituting the value of y we get
• 3/x + 3/1/7 = 36
• 3/x + 21 = 36
• 3/x = 36 – 21
• 3/x = 15
• Or x = 1/5

reference link will be

https://brainly.in/question/7229088