Question

(1+x)^10=a0+a1X+a2X^2+........................+a10x^10 and a2+(7/5)a1+1=0 then k=

Answer 1

Answer:

Step-by-step explanation:

( 1 + x ) ^n = 1 + nx + n ( n - 1 ) / 2! x² + .......

if  n =10 then a0 = 1 , a1 = 10 , a2 = 45

where is k ??????????

if a2 + 7/5 a1 + 1 = k

then 45 + 7/5 10 + 1 = 45 + 14 + 1 =60