Question

1/x^2-1 partial fraction

Answer 1

Hope u like my process
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$= > \bf \: \frac{1}{ {x}^{2} - 1} \\ \\ = \frac{1}{(x + 1)(x - 1)} \\ \\ = > \bf \: \frac{1}{ {x}^{2} } - 1 \\ \\ = \frac{1}{ {x}^{2} } (1 - {x}^{2} ) \\ \\ = \frac{1}{ {x}^{2} } (1 - x)(1 + x)$

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