Question

1/x-2+1/x-3+1/x-4=0 solve by formula​

Answer 1

Step-by-step explanation:

sorry I can't use any formula so may be this is right..m

Answer 2

Answer:

3, 4+(1-√13)/2, 4+(1+√13)/2

Step-by-step explanation:

1/x-2+1/x-3+1/x-4=0

(x-2)(x-3)+(x-2)(x-4)+(x-3)(x-4)=(x-2)(x-3)(x-4)

Lets substitute x-3=y, then we have:

y(y-1)+y(y+1)+(y-1)(y+1)=y(y-1)(y+1)

y^2-y+y^1+y+y^2-1=y(y^2-1)

3y^2=y^3-y

y(y^2-3y-1)=0

y=0, y =(3-√13)/2, y =(3+√13)/2

Finding x:

x=y+3

x=3, x=4+(1-√13)/2, x=4+(1+√13)/2