1/x+2 ,1/x+3 ,1/x+5 are in A.P find x ,How the LCM taken in this problem
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Answer:
x = 1
For solution , please refer to the attachment .
Note:
★ AP (Arithmetic Progression) : A sequence in which the difference between the consecutive terms are same .
★ If a , b , c are in AP then 2b = a + c and vice versa .
★ The general term of an AP is given by ;
T(n) = a + (n-1)d , where a is the first term and d is the common difference of the AP .
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a1=1/x+2
a2=1/x+3
a3=1/x+5
common difference=a2 - a1=a3 - a2
2(a2)=a3+a1
2(1/x+3)=1/x+2 + 1/x+5
2/x+3=(x+5+x+2)/(x+2)(x+5)
2/x+3=(2x+7)/x^2+7x+10
2x^2+14x+20=2x^2+13x+21
14x - 13x=20 - 21
x=1
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