Question

(1-x^2+2xy-y^2)/(x-1)

Answer 1

Answer:

1−x2−2xy−y2 is

Rearranging the terms

⇒ 1−(x2+2xy+y2)

⇒ −1(x+y)2 [∵ (x+y)2=x2+2xy+y2]

⇒ (1−(x+y)2)

⇒ (1)2=(x+y)2 [∵(1)2=1]

Using a2−b2=(a+b)(a−b)

⇒ (1−(x+y))(1+(x+y))

⇒ (1−x−y)(1+x+y) - solution

Step-by-step explanation:

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