Math, asked by Nolansia8074, 18 hours ago

1/(x-2)^3 solve by partial fraction

Answers

Answered by sahasneha05256
1

Answer:

1/(x^3-6x^2+12x-8)

Step-by-step explanation:

1/(x-2)^3

= 1/(x^3-3.x^2.2+3.x.2^2-2^3)

= 1/(x^3-6x^2+12x-8)

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