1/(x-2)^3 solve by partial fraction
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Answer:
1/(x^3-6x^2+12x-8)
Step-by-step explanation:
1/(x-2)^3
= 1/(x^3-3.x^2.2+3.x.2^2-2^3)
= 1/(x^3-6x^2+12x-8)
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