Question

(1-X)^-2 what is the expansion?
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Answer 1

Answer:

${(1 - x)}^{ - 2} \\ \\ = \frac{1}{ {(1 - x)}^{ 2} } \\ \\ = \frac{1}{ {x}^{2} + 1 - 2x} \\ \\ = \frac{1}{ {x}^{2} } + \frac{1}{1} - \frac{1}{2x} \\ \\ = {x}^{ - 2} + 1 - 2 {x}^{ - 1}$

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