Question

1.(X+2)(x+3)=0
2.(4x+3)(x-3)=0

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

$(x+2)(x+3)=0\\=x^{2}+2x+3x+6=0\\=x^{2} +5x+6=0\\x=-2, x=-3$     <=======1.

$(4x+3)(x-3)=0\\=4x^{2} +3x-12x-9=0\\=4x2-9x-9=0\\x=-\frac{3}{4} and x=3$<========2.