1/(x-2)(x-3) -1/(2-x)(3-x)
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1/(x-2)(x-3)-(1/(2-x)(3-x)
(x+a)(x+b)=x^2+(a+b)x+ab
(a+x)(b+x)=x^2+(a+b)x+ab
let x be'x'
a be '(-2)'
b be'(-3)'
= 1/(x)^2+[(-2)+(-3)]x+[(-2)(-3)] - 1/(x)^2+[(-2)+(-3)]x+[(-2)(-3)]
= 1/x^2+(-5)x+6 - 1/x^2+(-5)x+6
= 1/x^2-5x+6 - 1/x^2-5x+6
= 1-1/x^2-5x+6
= 0/x^2-5x+6
= 0
Therefore, the answer required is '0'
(x+a)(x+b)=x^2+(a+b)x+ab
(a+x)(b+x)=x^2+(a+b)x+ab
let x be'x'
a be '(-2)'
b be'(-3)'
= 1/(x)^2+[(-2)+(-3)]x+[(-2)(-3)] - 1/(x)^2+[(-2)+(-3)]x+[(-2)(-3)]
= 1/x^2+(-5)x+6 - 1/x^2+(-5)x+6
= 1/x^2-5x+6 - 1/x^2-5x+6
= 1-1/x^2-5x+6
= 0/x^2-5x+6
= 0
Therefore, the answer required is '0'
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