1-(x-2)-[(x-3)-(x-1)]=0
Answers
Answered by
0
Step-by-step explanation:
1-(x-2)-[x-3-x+1]=1-x+2-(-2)=5-x
Answered by
0
x = 3
Step-by-step explanation:
1-(x-2)-[(x-3)-(x-1)]=0
1-x-2-(x-3-x-1)=0
-1-x-(-4)=0
-1-x+4=0
3-x=0
x = 3
Hope it helps you. Thanks
Similar questions
Math,
28 days ago
Math,
28 days ago
Social Sciences,
1 month ago
Physics,
9 months ago
Science,
9 months ago