Math, asked by sauravkr85213760, 1 month ago

1-(x-2)-[(x-3)-(x-1)]=0​

Answers

Answered by jeffreleonce208
0

Step-by-step explanation:

1-(x-2)-[x-3-x+1]=1-x+2-(-2)=5-x

Answered by vrindagbn
0

x = 3

Step-by-step explanation:

1-(x-2)-[(x-3)-(x-1)]=0

1-x-2-(x-3-x-1)=0

-1-x-(-4)=0

-1-x+4=0

3-x=0

x = 3

Hope it helps you. Thanks

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