1-(x-2)-[(x-3)-(x-1)]=0
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Step-by-step explanation:
1-(x-2)-[(x-3)-(x-1)]=0
1-(x-2)-[(x-3-x+1)]=0
1-(x-2)-[(-2)]=0
1-(x-2)+2=0
1-x+2+2=0
x=5
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