Math, asked by rajatratnakar006, 2 months ago

1-(x-2)-[(x-3)-(x-1)]=0​

Answers

Answered by XxSweetPoisionxX
3

ʀᴇғᴇʀ ᴛᴏ ᴛʜᴇ ᴀᴛᴛᴀᴄʜᴍᴇɴᴛ !

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ✌

Attachments:
Answered by alphaace56
2

Answer:

HOPE IT WAS HELPFUL

Step-by-step explanation:

1-(x-2)-[(x-3)-(x-1)]=0

1-(x-2)-[(x-3-x+1)]=0

1-(x-2)-[(-2)]=0

1-(x-2)+2=0

1-x+2+2=0

x=5

Similar questions