1 - ( x - 2 ) - [ ( x - 3 ) - ( x - 1 ) ] = 0 Solve step by step
Answers
Answered by
45
1-(x-2)-[(x-3)-(x-1)]=0
1-(x-2)-[(x-3-x+1)]=0
1-(x-2)-[(-2)]=0
1-(x-2)+2=0
1-x+2+2=0
x=5
hope it helps you
1-(x-2)-[(x-3-x+1)]=0
1-(x-2)-[(-2)]=0
1-(x-2)+2=0
1-x+2+2=0
x=5
hope it helps you
Similar questions