Math, asked by dollyvictorya, 1 month ago

1 –(x – 2) – [(x – 3) – (x – 1)] = 0 ,the value of x is

Answers

Answered by Anonymous
2

Answer:

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Step-by-step explanation:

1  -  (x  -  2)  -  [(x  -  3)  -  (x  -  1)] = 0 \\  \\ 1  - (x   -  2)  -  [\cancel{x}  - 3 \:  \cancel{ -  x }+ 1] = 0 \\  \\ 1  - (x  - 2)  -  [ - 2] = 0 \\  \\ 1  - (x  - 2)  + 2 = 0 \\  \\ 1 - x + 2 + 2 = 0 \\  \\  - x + 5 = 0 \\  \\ \red{x = 5}

Answered by xSoyaibImtiazAhmedx
1

Answer:

1 –(x – 2) – [(x – 3) – (x – 1)] = 0

→ 1 – x + 2 – [ x – 3 – x + 1 ] = 0

→ 3 – x – [ – 2 ] = 0

→ 3 – x + 2 = 0

→ 5 – x = 0

x = 5

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