Question

(1-x)^2 + (x-x^2) + 3 =0

Answer 1

Answer:

number of real solutions of |2x-x^2-3|=1 is (a) 0 (b) - Doubtnut

When `2x-x^2-3 = -1` `=>-x^2+2x-2 = 0` `=>D = b^2-4ac = 2^2-4(-1)(-2) = 4-8 = -4 ` As, `D lt 0`, no real roots are present ...

Answer 2

Answer:

(1-x)² + (x-x²) +3=0

or, 1-2x+x²+x-x²+3=0

or, -x+4=0

or, x= -4

Hope it helps...