Question

(1-x)^2 +(x+y)^2=0 then x+y=?​

Answer 1

Answer:

${(1 - x)}^{2} + {(x + y)}^{2} = 0 \\ {(x + y)}^{2} = - {(1 - x) }^{2} \\ then \\ \: x + y = (1 - x)i \\ < i \: = \sqrt{ - 1} >$