Question

(1-x)^2+y^2=0 then (x+y) =?
answer = 1
plz explain​​

Answer 1

Answer:

x+y = 1+√(2y-2xy)

Step-by-step explanation:

${(1 - x)}^{2} + {y}^{2} = 0 \\ = > {(x - 1)}^{2} + {y}^{2} + 2(1 - x)y = 2(1 - x)y \\ = > {(x - 1 + y)}^{2} = 2y - 2xy \\ = > x - 1 + y = \sqrt{2y - 2xy} \\ = > x + y = 1 + \sqrt{2y - 2xy}$

in second line you probably noticed that I changed (1-x)² to (x-1)² because both are equal.

but remember 1-x ≠ x-1

I am not a pro, but I did what I could ...hope it helps :D