Question

1/x-2/y+4=0,1/y-1/z+1=0,2/z+3/x=14,find value of x,y,z​

Answer 1

Answer:

1/x=a

1/y=b

1/z=c

a-2b=-4......1

b-c=-1.......2

2c+2a=14.......3

from1 we have a=2b-4

from2 we have c=b+1

putting value of a and c in..... 3,we get

2c+2a=14

2c+2(2b-4)=14

2(b+1)+4b-8=14

2b+2+4b-8=14

6b-6=14

b-1=14/6=7/3

b=7/3+1=10/3

in .......1 we put b=10/3

a=2b-4a=2×10/3-4

a=8/3

put b=10/3 in ......2

c=b+1

c=10/3+1

c=13/3

1/x=a

1/×=8/3

×=3/8

1/y=b

1/y=10/3

y=3/10

1/z=c

1/z=13/3z=3/13