1/x-2y=1/3 & 1/x+2y=1/7 find the value of X
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let
1/x - 2y =1/3 - (1)
1/x + 2y = 1/7 - (2)
subtract (1) from (2)
1/x - 1/x + 2y - (- 2y ) = 1/7 - 1/3 ( taking l.c.m.)
0 +2y + 2y = 3-7/21
4y = -4/21
y = -4/21×4
y = -1/21
put value of y in (1)
1/x - 2(-1/21) = 1/3
1/x + 2/21 = 1/3
1/x = 1/3 - 1/21
1/x = 7-1/21
1/x =6/21
1/x = 2/7
x = 7/2
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1/x - 2y =1/3 - (1)
1/x + 2y = 1/7 - (2)
subtract (1) from (2)
1/x - 1/x + 2y - (- 2y ) = 1/7 - 1/3 ( taking l.c.m.)
0 +2y + 2y = 3-7/21
4y = -4/21
y = -4/21×4
y = -1/21
put value of y in (1)
1/x - 2(-1/21) = 1/3
1/x + 2/21 = 1/3
1/x = 1/3 - 1/21
1/x = 7-1/21
1/x =6/21
1/x = 2/7
x = 7/2
if my answer helps you.... pls mark as brainlist....
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