Math, asked by kawalpreetkaurd, 10 months ago

1/x-2y=1/3 & 1/x+2y=1/7 find the value of X

Answers

Answered by jadu9882
0
let
1/x - 2y =1/3 - (1)

1/x + 2y = 1/7 - (2)

subtract (1) from (2)

1/x - 1/x + 2y - (- 2y ) = 1/7 - 1/3 ( taking l.c.m.)

0 +2y + 2y = 3-7/21

4y = -4/21

y = -4/21×4

y = -1/21

put value of y in (1)

1/x - 2(-1/21) = 1/3

1/x + 2/21 = 1/3

1/x = 1/3 - 1/21

1/x = 7-1/21

1/x =6/21

1/x = 2/7

x = 7/2


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