Question

1/x+3+1/2x-1 =11/7x+9

Answer 1

to solve for x from the equation with fractions ?

$\frac{1}{x+3}+\frac{1}{2x-1}=\frac{11}{7x+9}\\\\\frac{2x-1+x+3}{2x^2+5x-3}=\frac{11}{7x+9}\\\\21 x^2+41x+18=22x^2+55x-33\\\\x^2+14x-51=0\\\\(x-3)(x+17)=0\\\\x=3\ or\ -17$

x = 3 or -17

Answer 2

Answer for the above question is very simple

X=3 and X=-17