Question

(1/x-3)-(1/x+5)=1/6( x not equal to3,-5)​

Answer 1

Step-by-step explanation:

$\frac{1}{x - 3} - \frac{1}{x + 5} = \frac{1}{6} \\ \\ \frac{(x + 5) - (x - 3)}{(x - 3)(x + 5)} = \frac{1}{6} \\ \\ \frac{ x + 5 - x + 3}{ {x}^{2} + 2x - 15} = \frac{1}{6} \\ \\ \frac{8}{ {x}^{2} + 2x - 15 } = \frac{1}{6} \\ \\ {x}^{2} + 2x - 15 = 48 \\ \\ {x}^{2} + 2x - 63 = 0 \\ \\ (x - 9 ) (x + 7)=0 \\ \\ therefore \: x=9 \: or \: x=-7$

Answer 2

Answer:

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