1+x+3=1343
x=54
how will the answer will 1343
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Answer:
9^x - 3^(x+1)-54=0
3^2x -3*3^x - 54 =0
let u = 3^x
u^2 -3u -54 = 0
u1,2 = [3+/-sqrt(9+4*54)]/2 =[3+/-15]/2
u1 = 9 = 3^2
u2 = -6,
but u =3^x
3^x1 = 3^2
x1=2
3^x2 = -6
log(3^x2) = log (-6), but the second term is not defined therefore eq excepts only x = 2
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