Question

(1) (x - 3)² = 49,vrag smikaran nikalo​

Answer 1

Answer:

$(x - 3) ^{2} = 49 \\ {x}^{2} + {3}^{2} - 2(x)(3) = 49 \\ [( {a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab] \\ {x}^{2} + 9 - 6x = 49 \\ {x}^{2} - 6x + 9 - 49 = 0 \\ {x}^{2} - 6x - 40 = 0 \\ By \: factorization, \\ {x}^{2} - 10x + 4x - 40 = 0 \\ x(x - 10) + 4(x - 10) = 0 \\ (x - 10)(x + 4) = 0$

Here,

x-10=0 (or) x+4=0

x=10 (or) x=(-4)

I hope it is helpful.

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