Question

1/x-3+2/x-2=8/x by factorization ​

Answer 1

pawri ho rhi h pa pa paddi ponu :P

Answer 2

Answer:

I assume you mean: [1/(x-3)]+[2/(x-2)]=8/x

Add the left side: (3x-8)/[(x-3)(x-2)]=8/x

Now cross multiply:x(3x-8)=8x2-40x+48

Collect terms: 5x2-32x+48=0

Factor: (5x-12)(x-4)=0